Asked by Anonymous
A 380- piano slides 3.8 down a 22 incline and is kept from accelerating by a man who is pushing back on it parallel to the incline.
a.Determine the force exerted by the man.
b.Determine the work done by the man on the piano.
c.Determine the work done by the force of gravity.
d.Determine the net work done on the piano. Ignore friction.
a.Determine the force exerted by the man.
b.Determine the work done by the man on the piano.
c.Determine the work done by the force of gravity.
d.Determine the net work done on the piano. Ignore friction.
Answers
Answered by
ajayb
a)As the acceleration is zero, the force exerted by the man equal the comp. of gravitational force on the body along the incline.
F = mg*Sin22
b)Wm = F.d
= - 3.8*F ( -ve because F and d are in opposite directions)
c) Wg = +3.8*mg*Sin22
d) Net force on piano = 0. So Wnet = 0
F = mg*Sin22
b)Wm = F.d
= - 3.8*F ( -ve because F and d are in opposite directions)
c) Wg = +3.8*mg*Sin22
d) Net force on piano = 0. So Wnet = 0
Answered by
Henry
post it.
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