Asked by Sammy
If Sin A=3/5 and cos B= -12/13, find the value of sin(A-B) if Angle A is in Quadrant I and angle B is in Quadrant III.
Answers
Answered by
Steve
in QI, sinA=3/5 means cosA = 4/5
in QIII, cosB = -12/13 means sinB = -5/13
sin(A-B) = sinAcosB - cosAsinB = (3/5)(-12/13) - (4/5)(-5/13) = (-36+20)/65 = -16/65
in QIII, cosB = -12/13 means sinB = -5/13
sin(A-B) = sinAcosB - cosAsinB = (3/5)(-12/13) - (4/5)(-5/13) = (-36+20)/65 = -16/65
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