Asked by Anonymous
O3 + NO --> O2 + NO2 (all in gas state)
Calculate the change in enthalpy for the reaction at room temp. using the following data
^Hf:
O3 = 143
NO = 90
NO2 = 33
So, I have 143+90--> X + 33. I don't know what the enthalpy of O2 is. I assume you simply subtract the enthalpy of products from the enthalpy of reactants. Is that correct?
Calculate the change in enthalpy for the reaction at room temp. using the following data
^Hf:
O3 = 143
NO = 90
NO2 = 33
So, I have 143+90--> X + 33. I don't know what the enthalpy of O2 is. I assume you simply subtract the enthalpy of products from the enthalpy of reactants. Is that correct?
Answers
Answered by
DrBob222
Yes, that is right.
delta H products - delta H reactants = delta H reaction. Delta H formatin for O2 is zero. However, let me point out that in your 143+90 ==> x + 33, you have reversed that process. You should have
DHrxn = 33 -(143 + 90)
delta H products - delta H reactants = delta H reaction. Delta H formatin for O2 is zero. However, let me point out that in your 143+90 ==> x + 33, you have reversed that process. You should have
DHrxn = 33 -(143 + 90)
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Toya
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