A cable attached to a block of mass 8 kg pulls the block along a horizontal floor at a constant velocity. If the tension in the cable is 5.3 N, what is the coefficient of kinetic friction between the block and the floor?

asked by Sierra

12 years ago

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1 answer

ma=0=T-F(fr) = T-μ•mg .
μ = T/mg = 5.3/8•9.8=0.068

answered by Elena

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Question

A cable attached to a block of mass 8 kg pulls the block along a horizontal floor at a constant velocity. If the tension in the cable is 5.3 N, what is the coefficient of kinetic friction between the block and the floor?

1 answer

ma=0=T-F(fr) = T-μ•mg .
μ = T/mg = 5.3/8•9.8=0.068

Elena · Accepted Answer

ma=0=T-F(fr) = T-μ•mg . μ = T/mg = 5.3/8•9.8=0.068