Asked by Lisa
A cylindrical object 0.5m in diameter and 2m long weights has a mass of 200kg. The object is floating end-down in water. How many cm of the object are above the waterline?
Answers
Answered by
Damon
A =cross section area = pi (.5)^2
1000 Kg/m^3 * A * (2-L) = mass of water displaced = 200
solve for L, multiply by 100 to get cm instead of meters
1000 Kg/m^3 * A * (2-L) = mass of water displaced = 200
solve for L, multiply by 100 to get cm instead of meters
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