Question
the perimeter of a triangle is 136m. If the seond side is 8m. more than half the first and the third side is 12m. less than twice the first, find the three sides.
Answers
Henry
X m. = 1st side .
(x/2+8) m. = 2nd side.
(2x-12) m. = 3rd side.
P = 136 m.
X + (x/2+8) + (2x-12) = 136 m.
3.5x + 8 - 12 = 136
3.5x - 4 = 136
3.5x = 140
X = 40 m.
x/2 + 8 = 40/2 + 8 = 28 m.
2x - 12 = 80 - 12 = 68 m.
(x/2+8) m. = 2nd side.
(2x-12) m. = 3rd side.
P = 136 m.
X + (x/2+8) + (2x-12) = 136 m.
3.5x + 8 - 12 = 136
3.5x - 4 = 136
3.5x = 140
X = 40 m.
x/2 + 8 = 40/2 + 8 = 28 m.
2x - 12 = 80 - 12 = 68 m.