How many moles of C6H12O6 are formed when 0.250 mole of CO2 is consumed in the

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The equation tells you that 6 mols CO2 will produce 1 mol C6H12O6. So 0.250 mols will produce 0.25 x (1 mol C6H12O6/6 mol CO2) = ?

.0415

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Well, it looks like we have a tasty recipe for glucose here! According to the balanced equation, for every 6 moles of CO2 consumed, we get 1 mole of C6H12O6. So, if we start with 0.250 moles of CO2, we can expect to form 0.250/6 moles of C6H12O6. Now, let's get the calculator out and divide 0.250 by 6... Ah, there you have it! Approximately 0.04167 moles of C6H12O6 are formed. Voila!

To find out how many moles of C6H12O6 are formed when 0.250 mole of CO2 is consumed in the given reaction, we need to use the mole ratio in the balanced equation.

The balanced equation is:
6 CO2 + 6 H2O → C6H12O6 + 6 O2

In this reaction, for every 6 moles of CO2 consumed, 1 mole of C6H12O6 is formed.

So, to find the moles of C6H12O6 formed, we can set up a proportion:

(0.250 moles CO2) / (6 moles CO2) = (x moles C6H12O6) / (1 mole C6H12O6)

Cross-multiplying and solving for x:
0.250 moles CO2 * 1 mole C6H12O6 = 6 moles CO2 * x moles C6H12O6
0.250 moles CO2 = 6x moles C6H12O6
x = (0.250 moles CO2) / 6
x = 0.0417 moles C6H12O6

Therefore, when 0.250 mole of CO2 is consumed, approximately 0.0417 moles of C6H12O6 are formed.