Question

If someone could help me get started or help me with the first few steps I could probably finish.

With Mass A = .500 kg
And
Mass B = .125 kg
Find the angle so that the system will be in equilibrium.

Answer 1

We don't have your diagram, so we don't know how the masses are connected.
Please describe your figure.

Answer 2

Oh sorry I completely forgot to add that part in. It's a right triangle and mass A is on the incline (hypotenuse) portion and is attached to a pulley and on the other end is mass B hanging down the side that would be the height of the triangle (opposite of the angle). Is that clear enough?

Answer 3

The tension in the string will be equal to T, which connects both masses A and B.

For mass A, the force down the incline is Ma*g*sin(θ) which equals T.

For mass B, the force due to gravity is Mb*g which also equals T.

Thus, equating the two values of T, we get:

Ma*g*sin(θ)=Mb*g

sin(θ)=Mb*g/(Ma*g)
=Mb/Ma
=0.125/0.5
=1/4

Can you take it from here?

Answer 4

Yea I got it! Thanks a lot!

Answer 5

You're welcome!