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A thin uniform rod (length = 1.3 m, mass = 4.1 kg) is pivoted about a horizontal frictionless pin through one of its ends. The...Asked by Tim
A thin uniform rod (length = 1.3 m, mass = 3.2 kg) is pivoted about a horizontal frictionless pin through one of its ends. The moment of inertia of the rod through this axis is (1/3)mL2. The rod is released when it is 50° below the horizontal. What is the angular acceleration of the rod at the instant it is released?
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Tim
I was able to figure this one out with a related question. Thank you!
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