A thin uniform rod (length = 1.3 m, mass = 3.2 kg) is pivoted about a horizontal frictionless pin through one of its ends. The moment of inertia of the rod through this axis is (1/3)mL2. The rod is released when it is 50° below the horizontal. What is the angular acceleration of the rod at the instant it is released?

asked by Tim

12 years ago

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I was able to figure this one out with a related question. Thank you!

answered by Tim

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A thin uniform rod (length = 1.3 m, mass = 3.2 kg) is pivoted about a horizontal frictionless pin through one of its ends. The moment of inertia of the rod through this axis is (1/3)mL2. The rod is released when it is 50° below the horizontal. What is the angular acceleration of the rod at the instant it is released?

1 answer

I was able to figure this one out with a related question. Thank you!

Tim · Answer

I was able to figure this one out with a related question. Thank you!