Asked by victoria
If 200 of the adults surveyed were in the age category of 24 and under and they provided a standard deviation of $14.50, construct a 95% confidence interval for the weekly average expenditure on fast food for adults 24 years of age and under. Assume fast food weekly expenditures are normally distributed.
Answers
Answered by
PsyDAG
95% = mean ± 1.96 SEm
SEm = SD/√n
Do you know the mean?
SEm = SD/√n
Do you know the mean?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.