Asked by victoria

If 200 of the adults surveyed were in the age category of 24 and under and they provided a standard deviation of $14.50, construct a 95% confidence interval for the weekly average expenditure on fast food for adults 24 years of age and under. Assume fast food weekly expenditures are normally distributed.

Answers

Answered by PsyDAG
95% = mean ± 1.96 SEm

SEm = SD/√n

Do you know the mean?
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