Asked by Yun Gao

The perfect pizza parlor estimates the average daily cost per pizza to be C(x) = (0.00025x^2 + 8x + 10)/x , where x is a number of pizzas made in a day.

a) determine the total cost at the level of production of 50 pizzas a day.

b) determine the production level that would minimize the average daily cost per pizza.

c) what is the minimum average daily cost per pizza?

Answers

Answered by Damon
cost per pizza at x = 50 is
[.00025(50)^2 + 8(50) +10 ]/50 = 8.21
* 50 = 410.63

dc/dx = [x (.0005 x + 8) -.00025x^2-8x-10) ]/x^2
when is the numerator zero?
.0005 x^2 + 8 x -.00025 x^2 -8 x -10 = 0
.00025 x^2 = 10
x = 200

for c, use 200 for x
Answered by drwls
(a) Plug in 50 for x and compute C(x).
(b) Solve for the value of x for which
C'(x) = dC(x)/dx = = 0.00025 x -20/x
= 0
25x^2 = 20,000

(c) Compute C(x) using the value of x from (b)
Answered by Yun Gao
thanks :)
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions