Asked by krishna
2.35*10^-4M,,Mg(OH)2
what is the pH of this solution
what is the pH of this solution
Answers
Answered by
DrBob222
Mg(OH)2 ==>Mg^2+ + 2OH^-
2.35E-4M = [Mg(OH)2]
(Mg^2+) = 2.35E-4
(OH^-) = 2*2.35E-4
pOH = 4.70E-4
pH + pOH = pKw = 14
You know pOH and pKw, solve or pH.
2.35E-4M = [Mg(OH)2]
(Mg^2+) = 2.35E-4
(OH^-) = 2*2.35E-4
pOH = 4.70E-4
pH + pOH = pKw = 14
You know pOH and pKw, solve or pH.
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