Asked by Leo
A car has a 12 volt battery. The engine has a resistance of 0.22 ohms. How many amps will be drawn from the battery when the key is turned?
Answers
Answered by
David E
V=IR
V= 12v
R= 0.22 ohms
I = V/R
= 12/0.22
=54.5 amps
V= 12v
R= 0.22 ohms
I = V/R
= 12/0.22
=54.5 amps
Answered by
Nancy
E= I x R is the formula
the answer is .5454
I=amperes
R=ohms
E=volts
12volts/22
the answer is .5454
I=amperes
R=ohms
E=volts
12volts/22
Answered by
Nancy
actually David is right. I forgot the decimal place from the 22 so it is 54.5 amps
Answered by
Leo
thank you
Answered by
Ushango
Three cells are connected. The external resistance of each cell is 2 ohms. The voltage of each cell is 1.5 volts. The resistance of the external circuit is 2.3 ohms. What is the circuit current to the nearest tenth ampere?
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