Asked by Anonymous
An air filled parallel plate capacitor initially has a capacitance of C = 4.57 nF.
Then the air gap between the plates is filled with two different dielectric materials with equal volume but with relative permittivities of å1 = 3.68 and å2 = 9.23 respectively. In the first case the dielectric materials are formed into two layers parallel to the plates of the capacitor. (See figure.) Determine the capacitance of the capacitor. (Note: the relative permittivity denoted by å is equivalent to the dielectric constant denoted by ê.)
Then the air gap between the plates is filled with two different dielectric materials with equal volume but with relative permittivities of å1 = 3.68 and å2 = 9.23 respectively. In the first case the dielectric materials are formed into two layers parallel to the plates of the capacitor. (See figure.) Determine the capacitance of the capacitor. (Note: the relative permittivity denoted by å is equivalent to the dielectric constant denoted by ê.)