Asked by kennisha
a boat travels 60 km due east. it then adjusts its course by 25 degrees northward and travels another 90 km in the new direction. how far is the boat from its initial position to the nearest kilometer?
Answers
Answered by
Henry
d = 60km @ 0 Deg. + 90 km @ 25 Deg.
X = Hor. = 60*cos(0) + 90*cos25 = 98 km.
Y = Ver. = 60*sin(0) + 90*sin25 =38 km.
d = sqrt((98)^2+(38)^2) = 105 km.
X = Hor. = 60*cos(0) + 90*cos25 = 98 km.
Y = Ver. = 60*sin(0) + 90*sin25 =38 km.
d = sqrt((98)^2+(38)^2) = 105 km.
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