Asked by Anonymous
A crate is given an initial speed of 2.9 up the 29 plane shown in the figure . Assume = 0.13
how far up the plane will it go?
how far up the plane will it go?
Answers
Answered by
Damon
Normal force = m g cos 29
friction force = .13 m g cos 29
call distance along surface headed up = d
work done against friction = .13 m g d cos 29
work done against gravity = m g d sin 29
so
(1/2) m v^2 = .13 m g d cos 29 + m g d sin 29
v^2 =2.9^2 = d (.13 cos 29 + sin 29)
solve for d which is distance sliding up ramp
if you want the final height it is d sin 29
friction force = .13 m g cos 29
call distance along surface headed up = d
work done against friction = .13 m g d cos 29
work done against gravity = m g d sin 29
so
(1/2) m v^2 = .13 m g d cos 29 + m g d sin 29
v^2 =2.9^2 = d (.13 cos 29 + sin 29)
solve for d which is distance sliding up ramp
if you want the final height it is d sin 29
Answered by
drwls
Symbols and units must be provided.
A statement like
"Assume = 0.13"
is meaningless by itself.
Damon has managed to figure out what you probably mean.
A statement like
"Assume = 0.13"
is meaningless by itself.
Damon has managed to figure out what you probably mean.
Answered by
Damon
LOL except I left out the 2 from the 1/2
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