Asked by Cindy L
Winborne has 35 coins consisting of dimes and nickels. If the value of his coins is $3.30 then how many of each type does he have?
Please help to check on correct answer
my answer is 31 dimes and 3 nickels
Please help to check on correct answer
my answer is 31 dimes and 3 nickels
Answers
Answered by
Anonymosu
Looks like you might have a typo there.
Total number of coins = 35
Number of dimes = x
Number of nickels nickels = 35 - x
Value of 1 dime = 0.10
Value of 1 nickel = 0.05
0.10x + 0.05(35 - x) = 3.30
0.10x + 1.75 - .05x = 3.30
0.05x = 1.55
x = 31 dimes
35 - 31 = 4 nickels
Total number of coins = 35
Number of dimes = x
Number of nickels nickels = 35 - x
Value of 1 dime = 0.10
Value of 1 nickel = 0.05
0.10x + 0.05(35 - x) = 3.30
0.10x + 1.75 - .05x = 3.30
0.05x = 1.55
x = 31 dimes
35 - 31 = 4 nickels
Answered by
Anonymosu
Oh no. Sorry about the extra "nickels"!
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.