Asked by Sara
Find sin2theta, cos2theta if csctheta=13/12 and lies in quadrant II.
Thank you!
Thank you!
Answers
Answered by
Reiny
If csc Ø = 13/12, the sinØ = 12/13
so we are dealing with the 12-5-13 right-angled triangle in II
then cosØ = -5/13
sin 2Ø = 2sinØcosØ
= 2(12/13)(-5/13)
= -120/169
cos 2Ø = cos^2 Ø - sin^2 Ø
= 25/169 - 144/169
= -119/169
so we are dealing with the 12-5-13 right-angled triangle in II
then cosØ = -5/13
sin 2Ø = 2sinØcosØ
= 2(12/13)(-5/13)
= -120/169
cos 2Ø = cos^2 Ø - sin^2 Ø
= 25/169 - 144/169
= -119/169
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.