Asked by Genny
The mass of the object was 8 kilograms. The object was acted on by a foce of 20 angle 80degrees newtons. What was the acceleration of the object?
Please walk me through the steps instead of just suggesting a formula..
Thank you!
Please walk me through the steps instead of just suggesting a formula..
Thank you!
Answers
Answered by
Henry
Your problem isn't very clear. So I'm
assuming that Fap = 20N @ 80 Deg and the object is on a level plane.
Fh = Fap*cos80 = 20*cos80 = 3.47 N. =
hor. component of Force applied.
a = Fh/m = 3.47 / 8 = 0.434 m/s^2.
assuming that Fap = 20N @ 80 Deg and the object is on a level plane.
Fh = Fap*cos80 = 20*cos80 = 3.47 N. =
hor. component of Force applied.
a = Fh/m = 3.47 / 8 = 0.434 m/s^2.
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