A particle moved along the x axis with a constant acceleration of -85.0 meters per second squared. The initial position of the particle was at the origin and its initial velocity was +325 meters per second. Find the position of the particle at T=4.0 seconds.

Question

Please walk through your steps,
Thank you very much.

Answer 1

v=vₒ-at.
Assume v=0, than
t= vₒ/a =325/85=3.82 s.
It takes 3.82 s. to stop, so after 4 s the particle
will be at rest at the point
x=vₒt-at²/2 =325•3.82 - 85•(3.82)²/2 =621.3 m

Answer 2

Thank you so much!!