Question

A car slowed down at a constant rate from 32meters per second to 3.0 meters per second in 9.0 seconds. What was the distance the car traveled in 9.00 seconds?

Please show all steps,
thank you very much.

Answer 1

You only need two steps for this.

Multiply 9.0 seconds by the AVERAGE velocity during the interval, which is (32 + 3)/2 = 17.5 m/s in this case.

9.0 * 17.5 = ____ m

Answer 2

v(final)=v,
v(initial) =vₒ,
v = vₒ -a•t,
a= (vₒ- v)/t=(32-3)/9=29/9=3.22 m/s².
s=vₒ•t- a•t ²/2=
=32•9 - 3.22•81/2 =157.6 m

Answer 3

Oh my goodness, thank you so much! I was trying to do so much more then I needed too!