Question
A car slowed down at a constant rate from 32meters per second to 3.0 meters per second in 9.0 seconds. What was the distance the car traveled in 9.00 seconds?
Please show all steps,
thank you very much.
Please show all steps,
thank you very much.
Answers
drwls
You only need two steps for this.
Multiply 9.0 seconds by the AVERAGE velocity during the interval, which is (32 + 3)/2 = 17.5 m/s in this case.
9.0 * 17.5 = ____ m
Multiply 9.0 seconds by the AVERAGE velocity during the interval, which is (32 + 3)/2 = 17.5 m/s in this case.
9.0 * 17.5 = ____ m
Elena
v(final)=v,
v(initial) =vₒ,
v = vₒ -a•t,
a= (vₒ- v)/t=(32-3)/9=29/9=3.22 m/s².
s=vₒ•t- a•t ²/2=
=32•9 - 3.22•81/2 =157.6 m
v(initial) =vₒ,
v = vₒ -a•t,
a= (vₒ- v)/t=(32-3)/9=29/9=3.22 m/s².
s=vₒ•t- a•t ²/2=
=32•9 - 3.22•81/2 =157.6 m
Jen
Oh my goodness, thank you so much! I was trying to do so much more then I needed too!