Asked by Jen
A car slowed down at a constant rate from 32meters per second to 3.0 meters per second in 9.0 seconds. What was the distance the car traveled in 9.00 seconds?
Please show all steps,
thank you very much.
Please show all steps,
thank you very much.
Answers
Answered by
drwls
You only need two steps for this.
Multiply 9.0 seconds by the AVERAGE velocity during the interval, which is (32 + 3)/2 = 17.5 m/s in this case.
9.0 * 17.5 = ____ m
Multiply 9.0 seconds by the AVERAGE velocity during the interval, which is (32 + 3)/2 = 17.5 m/s in this case.
9.0 * 17.5 = ____ m
Answered by
Elena
v(final)=v,
v(initial) =vₒ,
v = vₒ -a•t,
a= (vₒ- v)/t=(32-3)/9=29/9=3.22 m/s².
s=vₒ•t- a•t ²/2=
=32•9 - 3.22•81/2 =157.6 m
v(initial) =vₒ,
v = vₒ -a•t,
a= (vₒ- v)/t=(32-3)/9=29/9=3.22 m/s².
s=vₒ•t- a•t ²/2=
=32•9 - 3.22•81/2 =157.6 m
Answered by
Jen
Oh my goodness, thank you so much! I was trying to do so much more then I needed too!
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.