Asked by Jen

A car slowed down at a constant rate from 32meters per second to 3.0 meters per second in 9.0 seconds. What was the distance the car traveled in 9.00 seconds?

Please show all steps,
thank you very much.

Answers

Answered by drwls
You only need two steps for this.

Multiply 9.0 seconds by the AVERAGE velocity during the interval, which is (32 + 3)/2 = 17.5 m/s in this case.

9.0 * 17.5 = ____ m
Answered by Elena
v(final)=v,
v(initial) =vₒ,
v = vₒ -a•t,
a= (vₒ- v)/t=(32-3)/9=29/9=3.22 m/s².
s=vₒ•t- a•t ²/2=
=32•9 - 3.22•81/2 =157.6 m
Answered by Jen
Oh my goodness, thank you so much! I was trying to do so much more then I needed too!
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