Asked by Math Girl

a tugboat goes 160 miles upstream in 20 hours. The return trip downstream takes 10 hours. Find the speed of the tugboat without a current and the speed of the current.

Answers

Answered by Steve
if the speed of the boat in still water is x, and the speed of the current is c, then, remembering that distance=speed*time,

20(x-c)=10(x+c)
20x-20c=10x+10c
10x=30c
x=3c

20(2c) = 160
c = 4
so, x=12

check:
20(8) = 160
10(16) = 160
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