Asked by Kaelyn
A climber with a mass of 75 kg is attached to a 6.5 m rope with a cross sectional area of 3.5×10−4 m2. When the climber hangs from the rope, it stretches 3.4×10−3 m. What is the Young's modulus of the rope?
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Answers
Answered by
Elena
Young's modulus is
E = stress / strain,
E= F•L / A₀•ΔL = m•g•L / A₀•ΔL=
=75•9.8•6.5/3.5•10−4•3.4•10−3 =
=4•10^9 Pa.
E = stress / strain,
E= F•L / A₀•ΔL = m•g•L / A₀•ΔL=
=75•9.8•6.5/3.5•10−4•3.4•10−3 =
=4•10^9 Pa.