A cannonball of mass 6.09 kg is shot from a cannon at an angle of 47.18° relative to the horizontal and with an initial speed of 48.90 m/s. As the cannonball reaches the highest point of its trajectory, what is the gain in its potential energy relative to the point from which it was shot?

Answer 1

h =vₒ²sin²α/2g
ΔPE= m•g•h = m•g •vₒ²sin²α/2g