Asked by Jeconiah
If cos x >0 ans sin x= -4/5, then tan x=?
Answers
Answered by
Henry
sinx = -4/5 = b/c.
a^2 + b^2 = r^2
.a^2 + (-4)^2 = 5^2
a^2 = 5^2 - (-4)^2 = 9
a = +-3
a = 3(Cos>0).
tanx = b/a = -4/3.
a^2 + b^2 = r^2
.a^2 + (-4)^2 = 5^2
a^2 = 5^2 - (-4)^2 = 9
a = +-3
a = 3(Cos>0).
tanx = b/a = -4/3.
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