Antiderivative problem! Given f'(x)=3cosx–11sinx and f(0)=–2,find f(x)=

Answer 1

f(x) = 3 sin x + 11 cos x + c
f(0) = -2 = 3 (0) + 11 (1) + c
so c = -13
f(x) = 3 sin x + 11 cos x - 13