Asked by Yeneta

The solubility of sodium selenate is 84 g/100 g of water at 35 oC. If a solution is obtained by dissolving 92 g of sodium selenate in 200 g of water at 35 oC, What do you call this solution?
(A) Diluted
(B) Saturated
(C) Unsaturated
(D) supersaturated
Answered by DrBob222
92g/200 is the same as 46g/100. Since the solubility is 84/100, it certainly can't be saturated or supersaturated. So it must be .......
Answered by Betty
Answer
Answered by Toeln
To do the given exercise
Answered by Toeln
Give the answer of the given example
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