2S2O3 2- + I2 => S4o6 2- + 2I -
If,in an experiment,0.05 mol S2O3 2- is consumed in 1.0L of solution each second,at what rates are S4O6 2- and I- produced in this solution?
1 answer
S4O6^2- is 1/2*0.05M and I^- = 0.05M
If,in an experiment,0.05 mol S2O3 2- is consumed in 1.0L of solution each second,at what rates are S4O6 2- and I- produced in this solution?
1 answer
1 answer
2 answers
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2 answers