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obtain all zeros of x^4-7x^3+17x^2-17x+6 if two of its zeros are 3 and 1

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Do a division of x^4-7x^3+17x^2-17x+6 by (x-3)(x-1)=x²-4x+3 to get
x²-3x+2 as a quotient.
Factor x²-3x+2, equate to zero and solve for x.
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