Question

at 700 k the equilibrium constant for the reactions is Kp=0.76. Carbon tertrachrolide gas yields carbon solid and chlorine gas. A flask is charged with 2.00 atm of CCl4, which then reaches equilibrium at 700K. A) what is the fraction of the CCl4 is converted?
b) what are the partial pressures of CCl4 and Cl2 at equlibrium

Answer 1

........CCl4(g) ==> C(s) + 2Cl2(g)
I........2..........0........0
C.......-p..................+2p
E.......2-p.................+2p

Substitute into Kp expression and solve for p. 2p will give you pCl2 and 2-p will give you pCCl4.
For part a, fraction is pCl2/pCCl4