Asked by Count Iblis
Ideal Gas Law:
PV = N k T --->
N = PV/(k T)
N = 1.387*10^(29)
mass of one helium atom is approximately
4*u = 6.642*10^27 kg
4u*N = 921 kg
A Goodyear blimp typically contains 4770 m3 of helium (He) at an absolute pressure of 1.10 x 105 Pa. The temperature of the helium is 274 K. What is the mass (in kg) of the helium in the blimp?
I would help but my phisycs class is not as far as you yet.
Thanks
PV = N k T --->
N = PV/(k T)
N = 1.387*10^(29)
mass of one helium atom is approximately
4*u = 6.642*10^27 kg
4u*N = 921 kg
A Goodyear blimp typically contains 4770 m3 of helium (He) at an absolute pressure of 1.10 x 105 Pa. The temperature of the helium is 274 K. What is the mass (in kg) of the helium in the blimp?
I would help but my phisycs class is not as far as you yet.
Thanks