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A speed bike tops a hill at 3.5 m/s and accelerates steadily down hill reaching a speed of 11.4 m/s after 4.2 seconds. How far did the bike travel during this period?

2 answers

average speed=( 11.4+3.5 )/2

distance= avgspeed*time

a=(v-vₒ)/t
s= vₒ•t+at²/2

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