Asked by Francesca

Can someone please help me find the derivative of the following:

y = (-9e^7x) / (5x+3)

Thank you!
Answered by Kuai
y = (-9e^7x)/(5x+3)

y' = -9(35x^2+21x+3)*e^7x / (5x+3)^20
Answered by MathMate
Use the quotient rule:
d(u/v)=(vdu-udv)/v²
u=(-9e^(7x))
du/dx=-63e^7x
dv/dx=5
so
d(u/v)=((5x+3)(-63e^(7x))+9e^(7x)(5))/(5x+3)^2
=-9(35x+16)e^(7x)/(5x+3)²
Answered by Kuai
typo
There is typo
I do not know where I got power 20

-9( 35x+ 16 ) * e^7x /(5x+3)^2
Answered by Francesca
Thank you guys!
Answered by MathMate
You're welcome!
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