Asked by Anonymous
a car is moving on straight road with uniform acceleration .the speed of the car varies with time as of-4m/s,2 s-8m/s,so on till 10 seconds. Calculate the distance travelled in 10 seconds.
Asked 30 seconds ago under General Help
Asked 30 seconds ago under General Help
Answers
Answered by
drwls
What is the speed at t = 0?
When is the speed -8 m/s?
Why are the speeds negative?
When is the speed -8 m/s?
Why are the speeds negative?
Answered by
Elena
if we assume that
vₒ = - 4 m/s,
vb = - 8 m/s.
a =?, s = ?
v = vₒ +a•t,
a =(v- vₒ)/t = {-8 –(-4)}/10 = -0.4 m/s².
s= |vₒ|• t+a•t²/2 = 4•10 – 0.4•100/2 = 20 m.
(|vₒ| is the magnitude of initial velocity)
vₒ = - 4 m/s,
vb = - 8 m/s.
a =?, s = ?
v = vₒ +a•t,
a =(v- vₒ)/t = {-8 –(-4)}/10 = -0.4 m/s².
s= |vₒ|• t+a•t²/2 = 4•10 – 0.4•100/2 = 20 m.
(|vₒ| is the magnitude of initial velocity)
Answered by
Steve
since we have -4m/s^2 s-8m/s
it appears that
Vo = -8
a = -4
it appears that
Vo = -8
a = -4
Answered by
drwls
I find it impossible to interpret the problem as written. Take more care to separate sentences with a space and capitalize first words. Exponents must be preceded by ^. Velocity data at a specific time should clearly state the time as well as the velocity
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