Asked by Anonymous
a) While painting a 12 meter high roof you knock the paint brush off the edge, with no air resistance on the brush how long will it take to hit the ground?
b) What would the velocity of the brush be before it hit the ground?
b) What would the velocity of the brush be before it hit the ground?
Answers
Answered by
Anonymous
*While painting on a 12 meter high roof,
Answered by
Anonymous
Please check
12m= (0m/s)+1/2(9.81m/s^2)(t^2)
12m= 0+(4.905m/s^2)(t^2)
t^2=12/4.905m/s^2
t^2= 2.45s^2
t= 1.565 s
t= 1.6 s
12m= (0m/s)+1/2(9.81m/s^2)(t^2)
12m= 0+(4.905m/s^2)(t^2)
t^2=12/4.905m/s^2
t^2= 2.45s^2
t= 1.565 s
t= 1.6 s
Answered by
Anonymous
Velocity
12/1.6 sec= 7.5 meters/sec down
12/1.6 sec= 7.5 meters/sec down
Answered by
Elena
t= 1.565 s - correct
v =g•t =9.8•1.565 = 15.3 m/s
v =g•t =9.8•1.565 = 15.3 m/s
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