Asked by Devon
simplify:
(x^-2 - y^-2) / (x^-1 - y^-1)
i know you have to get rid of the negative powers, but i cant figure out how, any help?
(x^-2 - y^-2) / (x^-1 - y^-1)
i know you have to get rid of the negative powers, but i cant figure out how, any help?
Answers
Answered by
drwls
The numerator can be written
(x^-1 + y^-1)(x^-1 -y^-1)
One of the factors cancels the denominator, leaving you with
(x^-1 + y^-1)
Using a common denominator xy, that can be rewritten
(y + x)/xy
(x^-1 + y^-1)(x^-1 -y^-1)
One of the factors cancels the denominator, leaving you with
(x^-1 + y^-1)
Using a common denominator xy, that can be rewritten
(y + x)/xy
Answered by
Reiny
multiply top and bottom by (x^2y^2/(x^2y^2))
so
(x^2y^2/(x^2y^2))[(x^-2 - y^-2)/(x^-1 - y^-1)]
= (y^2 - x^2)/(xy^2 - x^2y)
= (y+x)(y-x)/[xy(y-x)]
= (y+x)/(xy)
I usually check a question like that by letting x and y be some numbers, and subbing that back in the original line and the final line.
Here I tried x=3 and y=4, and it worked.
so
(x^2y^2/(x^2y^2))[(x^-2 - y^-2)/(x^-1 - y^-1)]
= (y^2 - x^2)/(xy^2 - x^2y)
= (y+x)(y-x)/[xy(y-x)]
= (y+x)/(xy)
I usually check a question like that by letting x and y be some numbers, and subbing that back in the original line and the final line.
Here I tried x=3 and y=4, and it worked.
Answered by
Reiny
Wow, drwls saw an easier way.
Nice one!
Nice one!
Answered by
Devon
thank you!
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