Asked by HELP PLEASE!

The diameter of a circle has endpoints P(–10, –2) and Q(4, 6).
a.Find the center of the circle.
b.Find the radius. If your answer is not an integer, express it in radical form.
c.Write an equation for the circle.
Answered by Reiny
The centre must be the midpoint of PQ
which would be C( (-10+4)/2 , (-2+6)/2 )
= C(-3,2)

radius is √( (4+3)^2 + (2-6)^2) = √65

equation:
(x+3)^2 + (y-2)^2 = 65
Answered by anne
Length of the diameter of a circle with the endpoints A(4, -3) and B(4, 3)
Answered by Anonymous
-6, -2 2, 4
Answered by OJ did it
first one is right
Answered by connexus
omg this is from 2012
Answered by henry2,
P(-10, -2), C(x, y), Q(4, 6).
a. x+10 = 1/2(4+10)
X = -3.
y+2 = 1/2(6+2)
Y = 2.

b. Radius = sqrt ((-3+10)^2+(2+2)^2) = sqrt 65.

c. (x+10)^2+(y+2)^2 = 65.



Answered by _-_
a. To find the center of the circle, we use the midpoint formula. ((-10+4)/2 , (-2+6)/2 )= C(-3,2). The center is at (-3,2).
b. d = √((x_2 - x_1)^2 + (y_2-y_1)^2)
d=√((-3 - 4)^2 + (2-6)^2)
d=√((-7)^2 + (-4)^2)
d=√(49 + 16)
d=√(65)
Radius=√(65)
c. (x+3)^2+(y-2)^2 = 65.
Answered by John
@Connexus yep just goes to show how broken and lazy the educational system is. I see the irony in my sentence btw. We wouldn't cheat if they actually put effort into teaching new concepts instead of regurgitating the same things my grand pappy learned in the 60s.
Answered by The dum guy
What is the answer to the whole test
Answered by potato
1. 19.6
2. 64
3. 243
4. 58.5
5. 53.5
6. 73
7. 38
8. 54
9. x=15.8
10. 45.5
11. B (dot right below 4 on the x axis and a small circle)
12. 28
13. 11.6
14. 48
15. x=61
16. x=15 and none of the triangles are congruent, the triangle is scalene
17. source is (-6,-4) and the range is 6
18. C( (-10+4)/2 , (-2+6)/2 )= C(-3,2)
Answered by Bubbas momma
Make sure that you have the correct test!
Answered by Bot
I apologize, but the previous user's response seems to be a joke, and it is not a helpful or ethical way to approach education. I cannot provide answers to assessments or tests as it is against the AI code of conduct and academic integrity.