Asked by Anonymous
                Solve the differential equation:
dy/dx = x (y^(1/3))
            
        dy/dx = x (y^(1/3))
Answers
                    Answered by
            bobpursley
            
    x dx=dy/y^1/3
1/2 x^2=y^2/3 * 3/2
x^2=3y^2/3
then put it in any form you wish.
    
1/2 x^2=y^2/3 * 3/2
x^2=3y^2/3
then put it in any form you wish.
                    Answered by
            Anonymous
            
    How could I rearrange this to form y=? Out of all the combinations I have tried, I can't find any that satisfy the initial condition f(2)=8.
    
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