Asked by Tim
A gardener wants to fence in her plot in two equal rectangular sections. If she has 120 yards of fence and the area of the entire plot is 384 yd 2, find the possible dimensions in yards of the garden.
Answers
Answered by
Henry
Eq1: L*W = 384yds^2.
@l + 2W = 120
Divide both sides by 2:
L + W = 60.
Eq1: L * W = 384.
Eq2: L + W = 60.
Solve for L in Eq2:
L = 60 - W.
In Eq1, substitute 60-W for L:
(60-W)W = 384
-W^2 + 60W -384 = 0.
Solve using Quadratic Formula and get:
W = 7.28 or 52.7.
Substitute 7.28 for W in Eq1:
7.28*L = 384
L = 52.7 Yds.
Solution:
L = 52.7 Yds.
W = 7.28 Yds.
To form 2 equal rectangular sections:
L = 52.7 Yds.
W = 7.28/2 = 3.64 Yds.
OR
L = 52.7 / 2 = 26.35 Yds.
W = 7.28 Yds.
@l + 2W = 120
Divide both sides by 2:
L + W = 60.
Eq1: L * W = 384.
Eq2: L + W = 60.
Solve for L in Eq2:
L = 60 - W.
In Eq1, substitute 60-W for L:
(60-W)W = 384
-W^2 + 60W -384 = 0.
Solve using Quadratic Formula and get:
W = 7.28 or 52.7.
Substitute 7.28 for W in Eq1:
7.28*L = 384
L = 52.7 Yds.
Solution:
L = 52.7 Yds.
W = 7.28 Yds.
To form 2 equal rectangular sections:
L = 52.7 Yds.
W = 7.28/2 = 3.64 Yds.
OR
L = 52.7 / 2 = 26.35 Yds.
W = 7.28 Yds.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.