Asked by Amelia
What is the wavelength of an electron moving at 2.60% of the speed of light?
1 m
1 m
Answers
Answered by
Elena
v = 0.026•c
β = v/c = 0.026.
h = 6.63•10^-34 J•s
Relativistic momentum
p = mv/sqrt(1-β²) =
= 9.1•10^-31•0.026• 3•10^8 / sqrt(1 - 0.026²)=7.1•10^-24 kg•m/s.
de Broglie wavelength
λ = h/p = 6.63•10^-34/7.1•10^-24 =
=9.33•10^-11 m
β = v/c = 0.026.
h = 6.63•10^-34 J•s
Relativistic momentum
p = mv/sqrt(1-β²) =
= 9.1•10^-31•0.026• 3•10^8 / sqrt(1 - 0.026²)=7.1•10^-24 kg•m/s.
de Broglie wavelength
λ = h/p = 6.63•10^-34/7.1•10^-24 =
=9.33•10^-11 m
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