(a) ma = - mg + N
N = ma+mg
(b) 0= - mg + N
N =mg.
(c) -ma = - mg + N
N =mg - ma
A 79.2-kg person stands on a scale in an elevator. What is the apparent weight when the elevator is (a) accelerating upward with an acceleration of 1.92 m/s2, (b) moving upward at a constant speed, and (c) accelerating downward with an acceleration of 1.89 m/s2
I was going to use the equation
FN = mg + ma in which we are given a and mg but I was not sure what to use for m.
4 answers
so is 79.2 kg the value for mass(m) or mg?
Mass [s meeasured in kg.
Force (mg) - in Newtons.
m = 79.2 kg
Force (mg) - in Newtons.
m = 79.2 kg
A) a=1.92m/s^2
N-mg=ma
N=m(g+a)=79.2(10+1.92)=944 N
B) V=const, a=0
N-mg=0
N=mg=79.2*10=792 N
C) a=1.89m/s^2
N-mg=-ma
N=m(g-a) =79.2(10-1.89)=642.3 N
N-mg=ma
N=m(g+a)=79.2(10+1.92)=944 N
B) V=const, a=0
N-mg=0
N=mg=79.2*10=792 N
C) a=1.89m/s^2
N-mg=-ma
N=m(g-a) =79.2(10-1.89)=642.3 N
1 answer