Asked by Art
An electrom (qe = -1.6^-19 Coulomb) moves a distance of 0.170m in an 8.00 N/C electric field. Using appropriate formulas and a logical method, find the energy gained by the electrom.
Whoa ... how do I do this???
Whoa ... how do I do this???
Answers
Answered by
Elena
Energy = qe•Δφ=qe•E•s=
=1.6•10^-19•8•0.17 = 2.18•10^-19 J
=1.6•10^-19•8•0.17 = 2.18•10^-19 J
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