a ={v(final)² - v(initial)²}/2•s =
=(13.6² - 69.3²)/2•787= - 2.93 m/s²
1) A jetliner, traveling northward, is landing with a speed of 69.3 m/s. Once the jet touches down, it has 787 m of runway in which to reduce its speed to 13.6 m/s. Compute the average acceleration (magnitude and direction) of the plane during landing (take the direction of the plane's motion as positive).
I know that the formula for average acceleration is change in velocity / elasped time.
To get the change in velocity I did 69.3-13.6. I am not sure what the elasped time is.
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