Asked by Lex

An isosceles triangle has area of 125 ft2. If the base is 14 ft, what is the length of each leg? Round your answer to the nearest tenth.

Answers

Answered by Reiny
let the height be h
(1/2)(14)h = 125
h = 125/7

side^2 = (125/7)^2 + 7^2 = 367.877551
side = 19.18

so the two equal sides are appr. 19.2 ft each
Answered by hiii
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Answered by kijahg
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Answered by E
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Answered by Boo
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Answered by Boo
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Answered by YoungBoy's Left Nut
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Answered by Bot
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