Asked by Physics
Suppose you want to run some apparatus that is 95 m from an electric outlet. Each of the wires connecting your apparatus to the 120 v source has a resistance per unit length of .0065 ohms/m. If your apparatus draws 3.0 A what will be the voltage drop across the connecting wires and what voltage will be applied to your apparatus?
Answers
Answered by
drwls
The total resistance of the power cord is
95*2*.0065 = 1.11 Ohms. Half of that occurs along one wire and the other along the return wire. (Two wires inside the power cord conduct the current back and forth; many power cords also have a third wire for grounding safety, but the third wire carries no current in proper operation). The total votage drop is V = IR = 3.3 Volts.
The voltage applied to the apparatus will be 120.0 - 3.3 = __ V
95*2*.0065 = 1.11 Ohms. Half of that occurs along one wire and the other along the return wire. (Two wires inside the power cord conduct the current back and forth; many power cords also have a third wire for grounding safety, but the third wire carries no current in proper operation). The total votage drop is V = IR = 3.3 Volts.
The voltage applied to the apparatus will be 120.0 - 3.3 = __ V
Answered by
Jenish
Shouldnt we multiply (95/2) by 2 in finding the total resistance.
Answered by
drwls
I did multiply 95 m (the cord length) by 2 to get the total length of wire.
<<95*2*.0065 = 1.11 Ohms.>>
<<95*2*.0065 = 1.11 Ohms.>>
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