Asked by ashok
find dy/dx
y=3u^2-6u+2,u=v^2-1;v=2x
y=3u^2-6u+2,u=v^2-1;v=2x
Answers
Answered by
Reiny
dy/du = 6u - 6
du/dv = 2v
dv/dx = 2
dy/dx = (dy/du)(du/dv)(dv/dx)
= (6u-6)(2v)(2)
= 24v(u-1)
If necessary, use substitution of the originals to express in terms of whichever variable you want
du/dv = 2v
dv/dx = 2
dy/dx = (dy/du)(du/dv)(dv/dx)
= (6u-6)(2v)(2)
= 24v(u-1)
If necessary, use substitution of the originals to express in terms of whichever variable you want
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