Asked by khloe
A sign weighing 10N hangs from two ropes. Each rope is 45 degrees from the horizontal.
1. What is the tension in each rope?
1. What is the tension in each rope?
Answers
Answered by
drwls
Let T be the rope tension force in each. They are the same in each rope, due to symmetry.
2 T cos45 = 10 N (vertical equilibrium)
T = 10N * sqrt2 = 14.14 N
2 T cos45 = 10 N (vertical equilibrium)
T = 10N * sqrt2 = 14.14 N
Answered by
Henry
T1*sin(180-45) + T2*sin45 = -10*sin270.
0.707T1 + 0.707T2 = 10.
T1 = T2.
0.707T1 + 0.707T1 = 10.
1.414T1 = 10.
T1 = 7.07 N. = T2.
0.707T1 + 0.707T2 = 10.
T1 = T2.
0.707T1 + 0.707T1 = 10.
1.414T1 = 10.
T1 = 7.07 N. = T2.
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