Asked by emmie
A 65 kg bungee jumper leaps from a bridge. She is tied to a bungee cord that is 11m long when unstretched, and falls a total of 30m .
Part a) Calculate the spring constant of the bungee cord assuming Hooke's law applies.
part b)Calculate the maximum acceleration she experiences.
Part a) Calculate the spring constant of the bungee cord assuming Hooke's law applies.
part b)Calculate the maximum acceleration she experiences.
Answers
Answered by
drwls
When fully stretched X = 19 m beyond the unstretched length, the stored potential energy (k/2)*19^2 in the cord equals the gravitational potential energy loss, (M*g*30 m). Therefore,
k/2 = M*g*30/(19)^2 = 52.9
k = 105.8 N/m
k/2 = M*g*30/(19)^2 = 52.9
k = 105.8 N/m
Answered by
emmie
i got that answer but for part b i got 9.8 is that right ?
Answered by
drwls
No, there is a larger negative acceleration at maximum stretch. I am sorry I overlooked the second part of your question. Look for my answer in a later post.
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