Asked by Anonymous
evaluate the expression tan (257pi/4)
a.-1
b. -(sqrt2)/2
c. 1
d. (sqrt2)/2
a.-1
b. -(sqrt2)/2
c. 1
d. (sqrt2)/2
Answers
Answered by
MathMate
tan(x) has a period of π, so
tan(x)=tan(x+π),
in fact,
tan(x+kπ)=tan(x), where k∈Z
So to evaluate
tan(257π/4)
=tan((257/4)π)
=tan(64π + π/4)
=tan(π/4)
I will let you figure out which answer to choose.
tan(x)=tan(x+π),
in fact,
tan(x+kπ)=tan(x), where k∈Z
So to evaluate
tan(257π/4)
=tan((257/4)π)
=tan(64π + π/4)
=tan(π/4)
I will let you figure out which answer to choose.
Answered by
Anonymous
thank you so much, it helps! :)
Answered by
MathMate
You're welcome!
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