tan(x) has a period of π, so
tan(x)=tan(x+π),
in fact,
tan(x+kπ)=tan(x), where k∈Z
So to evaluate
tan(257π/4)
=tan((257/4)π)
=tan(64π + π/4)
=tan(π/4)
I will let you figure out which answer to choose.
evaluate the expression tan (257pi/4)
a.-1
b. -(sqrt2)/2
c. 1
d. (sqrt2)/2
3 answers
thank you so much, it helps! :)
You're welcome!