Question
A car is moving at the rate of 60 miles per hour, and the diameter of its wheels is 2.5 feet (1 mile=5280 feet)
a) Find the angular speed of the wheels in radians per minute
b) Find the number of revolutions per minute the wheels are rotating.
a) Find the angular speed of the wheels in radians per minute
b) Find the number of revolutions per minute the wheels are rotating.
Answers
I shouldve known better than to actually think i was gunna get help...
V = linear speed
r = radius
omega = angular velocity
RPM = Revolutions per minute
r = diameter / 2
60 mph = 60 * 5280 ft
V = r * omega
60 * 5280 = ( 2.5 / 2 ) * omega
316,800 = 1.25 omega Divide both sides ba 1,25
316,800 / 1.25 = omega
253,440 = omega
omega = 253,440 radians / h Divide both sides by 60
omega = 253,440/ 60
omega = 4,224 radians / min
1 rotation = 2 pi radians
RPM = 4,224 / 2 pi
RPM = 2112/ pi
RPM = 2112 / 3.1416
RPM = 672.2689 rotation / min
r = radius
omega = angular velocity
RPM = Revolutions per minute
r = diameter / 2
60 mph = 60 * 5280 ft
V = r * omega
60 * 5280 = ( 2.5 / 2 ) * omega
316,800 = 1.25 omega Divide both sides ba 1,25
316,800 / 1.25 = omega
253,440 = omega
omega = 253,440 radians / h Divide both sides by 60
omega = 253,440/ 60
omega = 4,224 radians / min
1 rotation = 2 pi radians
RPM = 4,224 / 2 pi
RPM = 2112/ pi
RPM = 2112 / 3.1416
RPM = 672.2689 rotation / min